If $n$ is the number density of free electrons in a metallic wire, then the resistance is proportional to

n

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n^{2}

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\frac{1}{n}

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\frac{1}{n^{2}}

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Solution

The correct option is B $\frac{1}{n}$
if a wire has a large number of free electrons then it would be easier for charge Q to travel through the wire and resistance of material will be low. Hence resistance is inversely proportional to the number of free electron in resister.

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