CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
532
You visited us 532 times! Enjoying our articles? Unlock Full Access!
Question

If N is the number of positive integral solutions of x1x2x3x4=770, then N=

A
256
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
729
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
292
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
770
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 256
First factorise 770.
770=2×5×7×11
We have, x1×x2×x3×x4=770
There are four prime factors of 770. Each of the prime factors can go to any of the four numbers.
For example - If 2 goes to x1, 5 goes to x2, 7 goes to x2 and 11 goes to x4, then x1=2,x2=35,x3=1 and x4=11

Similarly each of the 4 prime numbers have 4 numbers to go to. Hence, the total number of solutions is equal to
4×4×4×4=256

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Complement of a Set
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon