If n A - B - n A - n B - n A - B- then n A - B - -

We have, n( A ∪ B) = n( A ) + n( B ) n( A ∩ B) n( A ∩ B) = n( A ) + n( B ) n( A ∪ B) Hence, this is the answer. ...

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Cardinal Properties

If n A ∪ B ...

Question

If $n (A \cup B) = n (A) + n (B) - n (A \cap B)$ , then $n (A \cap B) = ?$

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