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Question

If n(μ)=48,n(A)=28, n(B)=33 and n(BA)=12, then n(AB)C is

A
27
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B
28
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C
29
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D
30
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Solution

The correct option is A 27
Given n(μ)=48,n(A)=28,n(B)=33,n(BA)=12
As we know that
n(BA)=n(B)n(AB)=33n(AB)
33n(AB)=12
n(AB)=3312=21
n(AB)C=n(μ)n(AB)=4821=27

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