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Question

If N=n! (nN, n>2) then ((log2N)1+(log3N)1+.....+(lognN)1] is

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Solution

(log2N)1+(log3N)1+.....+(lognN)1=logN2+logN3+.......+logNn=logN(2.3.4......n)=logN(n!)=logNN=1

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