If n number of identical resistors of resistance R are connected in parallel combination, then the effective resistance of the combination is ______

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n/R

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R/n

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n R - \frac{n}{R}

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Solution

The correct option is C R/n
For parallel combination we know that for equivalent resistance-

$\frac{1}{R_{e q}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} + . . .$

Here-

$\frac{1}{R_{e q}} = \frac{1}{R} + \frac{1}{R} + \frac{1}{R} + . . . n t i m e s$

$⟹ \frac{1}{R_{e q}} = \frac{n}{R}$

$⟹ R_{e q} = \frac{R}{n}$

Answer-(C)

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Similar questions

When $n$ resistors, each of resistance $R$ , are connected in series, the equivalent resistance is ___. When $n$ resistors, each of resistance $R$ , are connected in parallel, their equivalent resistance is ___.

Q. In the circuit shown, n identical resistors R are connected in parallel (n > 1) and the combination in series to another resistor

R_{0}

. In the adjoining circuit n resistors of resistance R are all connected in series along with

R_{0}

.
The batteries in both circuits are identical and net power dissipate in the n resistors in both circuit is same. The ratio

R_{0} / R

For $n$ resistors of equal resistances in combination, parallel connection gives larger effective resistance than the series connection.

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If n number of identical resistors of resistance R are connected in parallel combination, then the effective resistance of the combination is ______

The correct option is C R/nFor parallel combination we know that for equivalent resistance-1Req=1R1+1R2+1R3+...Here-1Req=1R+1R+1R+...ntimes⟹1Req=nR⟹Req=RnAnswer-(C)