If N t - N 0 e - t- then number of disintegrated atoms between t 1 to t 2 t 2- t 1 will beA- N0- e - t2- e - t1-B- N 0- e - t2- e - t 1-C- NoneD- N 0- e - t 1- e - t 2-

The correct option is D N_0[e^ λ t_1 e^ λ t_2]The number of nuclei at time t_1, N_1 nbsp;= N_0 e^ λ t_1 The number of nuclei at time t_2, N_2 = N_0 e^ λ t_2 ...

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Byju's Answer

Standard XII

Physics

Law of Radioactivity

If N t = N 0 ...

Question

If $N_{t} = N_{0} e^{- λ t}$ , then number of disintegrated atoms between $t_{1}$ to $t_{2}$ $(t_{2} > t_{1})$ will be

N_{0} [e^{λ t_{2}} - e^{λ t_{1}}]

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N_{0} [e^{- λ t_{2}} - e^{- λ t_{1}}]

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N_{0} [e^{- λ t_{1}} - e^{- λ t_{2}}]

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Solution

The correct option is C $N_{0} [e^{- λ t_{1}} - e^{- λ t_{2}}]$
The number of nuclei at time $t_{1}$ ,
$N_{1} = N_{0} e^{- λ t_{1}}$
The number of nuclei at time $t_{2}$ ,
$N_{2} = N_{0} e^{- λ t_{2}}$
Hence the number of disintegrated atoms between $t_{1}$ and $t_{2}$
= $N_{1} - N_{2}$
= $N_{0} [e^{- λ t_{1}} - e^{- λ t_{2}}]$

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If Nt=N0e−λt, then number of disintegrated atoms between t1 to t2 (t2>t1) will be

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