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General Form of an AP

If nth term...

Question

If $n^{t h}$ term of AP is $4 n + 1$ , then AM of $11^{t h}$ to $20^{t h}$ terms is

61.5

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63

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63.5

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62

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Solution

The correct option is D $63$
Given: $t_{n} = 4 n + 1$
$A . M . = \frac{t_{11} + t_{20}}{2}$
$= \frac{4 \times 11 + 1 + 4 \times 20 + 1}{2}$
$= 63$

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