If $n^{t h}$ term of AP is $t_{n} = 4 n + 1$ . Find mean of first $10$ terms.

85

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95

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23

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7.5

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Solution

The correct option is C $23$
Given:
$t_{n} = 4 n + 1$
$∴ A . M . = \frac{\sum_{n = 1}^{10} 4 n + 1}{n}$
$= \frac{2 n (n + 1) + n}{n}$
$= 2 n + 3$
$= 2 \times 10 + 3$
$= 23$

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