If nU - 48- nA - 28- nB - 33 and nB - A - 12- then nA - BC-

N(B – A) = n(B) – n(B ∩ A) ⇒ n(B ∩ A) = 33 − 12 = 21 ∴ n(A ∩ B)^C nbsp;= n(U) – n(A ∩ B) = 48 − 21 = 27 ...

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If nU = 48, n...

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If $n (U) = 48, n (A) = 28, n (B) = 33$ and $n (B - A) = 12$ , then $n (A \cap B)^{C} =$

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