If nU - 48- nA - 28- nB - 33 and nB - A - 12- then nA - BC-

N(B – A) = n(B) – n(B ∩ A) ⇒ n(B ∩ A) = 33 − 12 = 21 ∴ n(A ∩ B)^C nbsp;= n(U) – n(A ∩ B) = 48 − 21 = 27 ...

You visited us 71 times! Enjoying our articles? Unlock Full Access!

Complement of a Set

If nU = 48, n...

Question

If $n (U) = 48, n (A) = 28, n (B) = 33$ and $n (B - A) = 12$ , then $n (A \cap B)^{C} =$

27

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

28

No worries! We‘ve got your back. Try BYJU‘S free classes today!

29

No worries! We‘ve got your back. Try BYJU‘S free classes today!

30

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

n (U) = 48, n (A) = 28, n (B) = 33

n (B - A) = 12

n (A \cap B)^{C} =

n (U) = 48, n (A) = 28, n (B) = 33

n (B - A) = 12

n (A \cap B)^{C} =

n (U) = 48, n (A) = 28, n (B) = 33

n (B - A) = 12

n {(A \cap B)}^{C}

U

n (μ) = 48, n (A) = 28

n (B) = 33

n (B - A) = 12

n (A \cap B)^{C}

n (U) = 700, n (A) = 200, n (B) = 300

n (A \cap B) = 100

n (A^{c} \cap B^{c}) =

Join BYJU'S Learning Program