Question

If NaCl is doped with ${10}^{-3}mol$% $SrC{l}_2$, then the concentration of cation vacancies will be

• A. 1 x 10^-3 mol%
• B. 2 x 10^-3 mol%
• C. 3 x 10^-3 mol%
• D. 4 x 10^-3 mol%

Answer 1

The correct option is A 1 x 10^-3 mol%

Each $S{r}^2+$ ion introduces one cation vacancy
$\Rightarrow$ number of cation vacancies = % mole of $S{r}^{2+}={10}^{-3}mol$%