200

You visited us 200 times! Enjoying our articles? Unlock Full Access!

Solubility

If NaCl is do...

Question

If NaCl is doped with then the concentration of cation vacancies will be

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A

As each Sr²⁺ ion introduces one cation vacancy, therefore concentration of
cation vacancies = mol % of SrCl₂ added.

Suggest Corrections

Similar questions

10^{- 3} m o l

S r C l_{2}

10^{- 3} m o l

S r C l_{2}

N a C l

10^{- 4}

{S r C l}_{2}

N a C l

10^{- 3}

S r C l_{2}

N a C l

N a C l

10^{- 4} m o l %

S r C l_{2}

(N_{A} = 6.02 \times 10^{23} m o l^{- 1})

Join BYJU'S Learning Program