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Concentration Terms

If NaHC2O4 ...

Question

If $N a H C_{2} O_{4}$ behaves as a reducing agent. Its equivalent weight is:

E = \frac{M}{2}

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E

=

M

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E = \frac{M}{3}

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none of these

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Solution

The correct option is D $E = \frac{M}{2}$
$C_{2} O_{4}^{-} + 6 ⟶ {C O}_{2} + 8 + 2 e^{-}$ (for two $C -$ atoms)
Change in oxidation number $= 2$ units
Thus, equivalent weight $= \frac{m o l e c u l a r w e i g h t}{2}$

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