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Standard XII

Chemistry

Pauli's Exclusion Principle

If nitrogen a...

Question

If nitrogen atom had an electronic configuration of $1 s^{7}$ , it would have energy lower than it’s normal ground state configuration of $1 s^{2} 2 s^{2} 2 p^{3} . Y e t, 1 s^{7}$ is not observed as it violates:

Bohr postulates

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Hund' s rule

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Pauli' s exclusion principle

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Bohr-Bury rule

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Solution

The correct option is C Pauli' s exclusion principle
This configuration violates Pauli’s exclusion principle as one orbital cannot have more than two electrons.

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Similar questions

Q. If the nitrogen atom had an electronic configuration of

1 s^{7}

it would have lower energy than that of the normal ground state configuration

1 s^{2}, 2 s^{2}, 2 p^{3}

because the electrons would be closer to the nucleus.

1 s^{7}

is not observed because it violates:

Q. If the nitrogen atom had electronic configuration

1 s^{7}

, it would have energy lower than that of the normal ground state configuration

1 s^{2} 2 s^{2} 2 p^{3}

, because the electrons would be closer to the nucleus. Yet

1 s^{7}

is not observed because it violates:

If carbon atom has electronic configuration 1 $s^{6}$ , it would have energy lower than that of the normal ground state configuration 1 $s^{2}$ 2 $s^{2}$ 2 $p^{2}$ . Yet 1 $s^{6}$ is not observed because it violates

Q. If the nitrogen atom had electronic configuration

1 S^{7}

, it would have enrgy lower than that of the normal ground state configuration

1 s^{2}, 2 s^{2}, 2 p^{3}

, because the electrons would be closer to the nucleus. Yet

1 s^{7}

is not observed because it violates.

Q. If carbon has electronic configuration

1 s^{6}

, it would have lower energy than that of the normal ground state configuration

1 s^{2} 2 s^{2} 2 p^{2}

, because the electrons would be closer to the nucleus. Yet

1 s^{6}

is not observed, since it violates

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If nitrogen atom had an electronic configuration of 1s7, it would have energy lower than it’s normal ground state configuration of 1s22s22p3.Yet,1s7 is not observed as it violates:

The correct option is C Pauli' s exclusion principleThis configuration violates Pauli’s exclusion principle as one orbital cannot have more than two electrons.

If nitrogen atom had an electronic configuration of $1 s^{7}$ , it would have energy lower than it’s normal ground state configuration of $1 s^{2} 2 s^{2} 2 p^{3} . Y e t, 1 s^{7}$ is not observed as it violates:

The correct option is C Pauli' s exclusion principle
This configuration violates Pauli’s exclusion principle as one orbital cannot have more than two electrons.