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Question

​If non-coplanar vectors a, b, c from a parallelopiped of volume 6 cubic units, then the values of a+b b+c c+a are _______________.

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Solution

For noncoplanar vectors a, b and c.Given volume of parallelopiped is 6 cubic unitsThen a+b b+c c+a=a+b×b+c·c+a By defination=a×b+a×c+b×b+b×c·c+a By distributive law=a×b+a×c+0+b×c·c+a b×b=0=a×b·c+a×c·c+b×c·c+a×b·a+a×c·a+b×c·a=a×b·c+0+0+0+0+b×c·a two vectors of scalar triple product is zero=+a b c+a b c=±2 a b c=±2×6=±12i.e a+b b+c c+a=±12

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