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Question

If non-zero vectors a and b are equally inclined to coplanar vector c, then c can be

A
aa+2ba+ba+bb
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B
|b||a|+|b|a+|a||a|+|b|b
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C
|a||a|+2|b|a+|b||a|+2|b|b
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D
|b|2|a|+|b|a+a2|a|+bb
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Solution

The correct options are
B |b||a|+|b|a+|a||a|+|b|b
C |b|2|a|+|b|a+a2|a|+bb
Since a and b are equally inclined to c,c must be of the form ta|a|+b|b|
Now |b||a|+|b|a+|a||a|+|b|b
=|a||b||a|+ba|a|+b|a|+|b|
Also, |b|2|a|+|b|a+|a|2|a|+|b|b
=|a|+|b|2|a|+ba|a|+b|b|
Other two vectors cannot be written in the form ta|a|+b|b|

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