Question

If normal body temperature is ${98.6}^{o}F$, then the temperature in Celsius is

• A. ${37}^{o}C$
• B. ${42}^{o}F$
• C. ${46}^{o}F$
• D. ${53}^{o}F$

Answer 1

The correct option is A ${37}^{o}C$

Conversion of temperature is

${}^{\circ }F=\frac{9}{5}{\times }^{\circ }C+{32}^{\circ }{\Rightarrow }^{\circ }C=\frac{5}{9}{(}^{\circ }F-{32}^{\circ })$

For ${98.6}^{\circ }F$

${}^{\circ }C=\frac{5}{9}({98.6}^{\circ }-{32}^{\circ }){}^{}{}^{\circ }C=\frac{5}{9}\times {66.6}^{\circ }={37}^{\circ }$