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Multiplying Terms with the Same Base

If nPr =302...

Question

If $^{n} P_{r} = 3024$ , then $(n, r) =$

A

(8, 4)

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B

(8, 3)

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C

(9, 3)

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D

(9, 4)

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Solution

The correct option is D $(9, 4)$
$^{n} P_{r} = 3024 = 72 \times 42 = 9 \times 8 \times 7 \times 6 = \frac{9!}{(9 - 4)!} =^{9} P_{4}$
Hence $(n, r) = (9, 4)$

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Similar questions

^{n} P_{r}

=

(n, r)

=

^{n} P_{r} =^{n} P_{r + 1}

^{n} C_{r} =^{n} C_{r - 1}

, then the values of

n

r

^{n} P_{r} =^{n} P_{r}_{+}_{1}

^{n} C_{r} =^{n} C_{r}_{-}_{1}

, then the values of n and r are:

^{n} P_{r} =

30240

^{n} C_{r} =

252

, then the ordered pair

(n, r)

=

^{n} P_{r} =^{n} P_{r + 1}

^{n} C_{r} =^{n} C_{r - 1}

, find n and r.

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