If number of terms in the expansion of (x−2y+3z)n are 45, then n =
7
8
9
None of these
(n+1)(n+2)2 = 45 or n2 + 3n - 88 = 0 ⇒ n = 8 .
If in the expansion of (1+x)n, the coefficients of three consecutive terms are 56, 70 and 56, then find n and the position of the terms of these coefficients.
If number of terms in the expansion of
(x−2y+3z)n are 45, then n =