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Byju's Answer

Standard VI

Chemistry

Respiration

If O 2 conce...

Question

If O $_{2}$ concentration in tissue was almost as high as at the respiratory surface

Oxyhaemoglobin would dissociate to supply to the tissue

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Haemoglobin would combine with more O

_{2}

at respiratory surface

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Oxyhaemoglobin would not dissociate to supply O

_{2}

to the tissue

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_{2}

will interfere the O

_{2}

transport

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Solution

The correct option is C Oxyhaemoglobin would not dissociate to supply O $_{2}$ to the tissue
When the oxygen concentration in tissue is high then oxygen dissociation curve shifts to the left. A right shift of the hemoglobin dissociation curve causes a decrease in the affinity of hemoglobin for oxygen. This makes it harder for the hemoglobin to bind to oxygen and makes it easier for the hemoglobin to release bound oxygen. Conversely, a left shift of the hemoglobin dissociation curve increases the affinity, making the oxygen easier for the hemoglobin to pick up but harder to release.

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Similar questions

Q. When

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N_{2} O_{5} (g) ⇌ N_{2} O_{3} (g) + O_{2} (g); K_{c} = 2.5

. At the same time

N_{2} O_{3}

also decomposes as:

N_{2} O_{3} (g) ⇌ N_{2} O + O_{2} (g)

. If initially

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N_{2} O_{5}

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N_{2} O_{5} (g) ⇌ N_{2} O_{3} (g) + O_{2} (g); K_{c} = 2.5

. At the same time

N_{2} O_{3}

also decomposes as:

N_{2} O_{3} (g) ⇌ N_{2} (g) + O_{2} (g);

. If 4.0 moles of

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Q. The equilibrium constant for the equilibrium (at 1000 K)

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K = 1.20

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Q. When

N_{2} O_{5}

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N_{2} O_{5} ⇌ N_{2} O_{3} + O_{2}, K_{e} = 2.5

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N_{2} O_{3}

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N_{2} O_{3} ⇌ N_{2} O + O^{2}

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N_{2} O_{5}

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The respiratory centre in the brain is stimulated by $C O_{2}$

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If O2 concentration in tissue was almost as high as at the respiratory surface

If O $_{2}$ concentration in tissue was almost as high as at the respiratory surface