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Question

If ω is a complex cube root of unity and (1+ω)7 = A + Bω , then (A, B) is


A

0,1

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B

1,0

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C

1,1

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D

-1,-1

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Solution

The correct option is C

1,1


We know the relation 1 + ω + ω2 = 0
1 + ω = - ω2
(1+ω)7 = (ω2)7 = - (ω)14
= - ω12ω2
= - (ω3)4 ω2
= - ω2

1 + ω = -ω2
A + Bω = 1 + ω
A = 1 , B = 1


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