If O is the circumcentre of ΔABC and R1,R2 and R3 are the radii of the circumcircles of triangles OBC,OCA and OAB, respectively, then aR1+bR2+cR3 has the value equal to
A
abcR3
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B
R3abc
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C
4ΔR2
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D
Δ4R2
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Solution
The correct options are AabcR3 D4ΔR2 If O is the circumcentre of ΔABC, then OA=OB=OC Let R1,R2 and R3 be circumradii of ΔOBC,ΔOCA and ΔOAB respectively. In ΔOBC,2R1=asin2A⇒aR1=2sin2A SimilarlybR2=2sin2B and cR3=2sin2C ⇒aR1+bR2+cR3=2(sin2A+sin2B+sin2C)=8sinAsinBsinC