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Question

If O is the circumcentre of ΔABC and R1,R2 and R3 are the radii of the circumcircles of triangles OBC,OCA and OAB, respectively, then aR1+bR2+cR3 has the value equal to

A
abcR3
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B
R3abc
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C
4ΔR2
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D
Δ4R2
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Solution

The correct options are
A abcR3
D 4ΔR2
If O is the circumcentre of ΔABC, then OA=OB=OC Let R1,R2 and R3 be circumradii of ΔOBC,ΔOCA and ΔOAB respectively.
In ΔOBC,2R1=asin2AaR1=2sin2A
SimilarlybR2=2sin2B and cR3=2sin2C
aR1+bR2+cR3=2(sin2A+sin2B+sin2C)=8sinAsinBsinC
=8a2Rb2RC2R=abcR3

This is also equal to 4ΔR2

111152_72238_ans_b00657006d4e41d58a12d30b600e94fc.png

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