If O is the origin and OP,OQ are distinct tangents to the circle x2+y2+2gx+2fy+c=0 the circumcentre of the triangle OPQ is
A
(−g,−f)
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B
(g,f)
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C
(−f,−g)
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D
None of these.
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Solution
The correct option is D None of these. Since PQ is the chord of contact of the tangents from the origin O to the circle x2+y2+2gx+2fy+c=0,(1)
Equation of PQ is gx+fy+c=0(2)
An equation of a circle through the intersection of (1) and (2) is given by x2+y2+2gx+2fy+c+λ(gx+fy+c)=0(3) If, the circle (3) passes through origin, then c+λc=0, i.e λ=−1 and the equation of the circle (3) becomes x2+y2+gx+fy=0
Centre of this circle is (−g/2,−f/2), and hence it is the circumcentre of the triangle OPQ