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Question

If O is the origin and OP,OQ are distinct tangents to the circle x2+y2+2gx+2fy+c=0 the circumcentre of the triangle OPQ is

A
(g,f)
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B
(g,f)
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C
(f,g)
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D
None of these.
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Solution

The correct option is D None of these.
Since PQ is the chord of contact of the tangents from the origin O to the circle
x2+y2+2gx+2fy+c=0,(1)

Equation of PQ is gx+fy+c=0(2)

An equation of a circle through the intersection of (1) and (2) is given by
x2+y2+2gx+2fy+c+λ(gx+fy+c)=0(3)
If,
the circle (3) passes through origin, then c+λc=0, i.e λ=1
and the equation of the circle (3)
becomes x2+y2+gx+fy=0

Centre of this circle is (g/2,f/2), and hence it is the circumcentre of the triangle OPQ

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