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Question

If OA and OB be the tangents to the circle x2+y26x8y+21=0 drawn from the origin O, then AB = 


  1. 11

  2. 12


Solution

The correct option is C


Here the equation of AB(chord of contact) is

0+03(x+0)4(y+0)+21=0

3x+4y21=0             ...(i)

CM = perpendicular distance from (3,4) to line (i) is

3×3+4×4219+16=45

AM = AC2CM2=41625=2521

AB=2AM=4521

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