If object is placed at 60 cm before lens I focal length of lens I is 30 cm and focal length of lens II is 45 cm. find out the image distance formed by lens II from O?

180 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

120 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

60 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

90 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
180 cm

For lens I, since object is at 2f (i.e. 60 cm) image of lens I is formed at 60 cm from a between lens I & II.

$\frac{1}{v}$ - $\frac{1}{u}$ = $\frac{1}{f}$

$\frac{1}{(v)}$ + $\frac{1}{60}$ = $\frac{1}{45}$

$\Rightarrow$ v = 180 cm

Suggest Corrections

Similar questions

Focal length of convex lens is 20 cm, focal length of concave mirror is 30 cm. And the separation between lens and mirror is 90 cm. If the object is placed 60 cm before lens, find out position of image formed by concave mirror?

The focal length of a convex lens is $20 c m$ , the focal length of the concave mirror is $30 c m$ . And the separation between lens and mirror is $90 c m$ . If the object is placed $60 c m$ before the lens, find out the position of an image formed by the concave mirror?

Q. Flat surface of a plano-convex lens of focal length 20 cm is silvered. If object is placed at 60 cm from lens then distance of image from lens is

A lens forms an image of an object which is placed at a distance 15 cm in front of it. if the image forms at a distance 60 cm on the same side Find : (i) the focal length, (ii) the magnification, and (iii) the nature of image.

Q. A convex lens, of focal length

30 c m

, a concave lens of focal length

120 c m

, and a plane mirror are arranged as shown. For an object kept at a distance of

60 c m

from the convex lens, the final image, formed by the combination, is a real image, at a distance of :

Join BYJU'S Learning Program

If object is placed at 60 cm before lens I focal length of lens I is 30 cm and focal length of lens II is 45 cm. find out the image distance formed by lens II from O?

The correct option is A 180 cm For lens I, since object is at 2f (i.e. 60 cm) image of lens I is formed at 60 cm from a between lens I & II. 1v - 1u = 1f 1(v) + 160 = 145 ⇒ v = 180 cm

The correct option is A
180 cm

For lens I, since object is at 2f (i.e. 60 cm) image of lens I is formed at 60 cm from a between lens I & II.

$\frac{1}{v}$ - $\frac{1}{u}$ = $\frac{1}{f}$

$\frac{1}{(v)}$ + $\frac{1}{60}$ = $\frac{1}{45}$

$\Rightarrow$ v = 180 cm