Question

If OD is perpendicular to AB, and ∠DOC = 25°, find ∠BOC - ∠AOC.

• A. 25°
• B. 65°
• C. 115°
• D. 50°

Answer 1

The correct option is D

50°

From the given figure, given $\angle BOD={90}^{\circ }$ and $\angle DOC={25}^{\circ }$
$\therefore \angle BOC={115}^{\circ }$
$\angle AOC=\angle DOA-\angle DOC$
$\angle AOC={90}^{\circ }-{25}^{\circ }={65}^{\circ }$
$\therefore \angle BOC-\angle AOC$
$={115}^{\circ }-{65}^{\circ }={50}^{\circ }$