Question

If oil is transferred from rectangular container of dimension $4$ meters by $9$ meters by $10$ meters into a cylindrical container of diameter $12$ meters, then the minimum length for a cylindrical container that will hold all of the oil is

• A. $80\pi$
• B. $\frac{10}{\pi }$
• C. $120\pi$
• D. $\frac{20}{\pi }$

Answer 1

The correct option is B $\frac{10}{\pi }$

Volume of cylinder $=$ volume of rectangular container
$\pi r^{2}h=4\times 9\times 10$
$d=12,r=$ half of diameter $=6$ m
Therefore, $\pi (6{)}^2\times h=360$
$h=\frac{10}{\pi }$m