Question

If 'OLYMPIAD' is the unit of a new physical quantity. How many times more then 1 Mega OLYMPIAD when compared to ten milli OLYMPIAD ?

Answer 1

We kniow that,
1 Mega olympiad ${10}^6$ olympiad ................. (1)
10 milli olympiad $={10}^{-2}$ olympiad ............. (2)
Dividing (1) by (2) we get
$\frac{1Megaolympiad}{10milliolympiad}=\frac{{10}^{6}olympiad}{{10}^{-2}olympiad}$
$=\frac{{10}^6}{{10}^{-2}}={10}^8$
$\therefore \frac{1Megaolympiad}{10milliolympiad}={10}^8$
$\Rightarrow$ 1 Mega olympiad $={10}^8$ ten milli olympiad.