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Question

If ω = 1+i32 , then Z1 = 3i2 and Z2 = 3i2 can be expressed in terms of ω and ω2 as


A

-i , i

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B

i , - i

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C

i , i

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D

-i , -i

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Solution

The correct option is C

i , i


ω is a cube root of unity . Then ω2 = 1i32

Z1 = 3i2 = i 1+i32
= iω

Z2 = 3i2 = i (1i3)2
= iω2


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