If - is a complex cube root of unity with - 1 and p-pij- is a n- n matrix with pij-i-j- Then- p2 0- when n is equal to

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Expansion of (x+y)^3

If ω is a c...

Question

If $ω$ is a complex cube root of unity with $ω \neq 1$ and $p = [p_{i j}]$ is a $n \times n$ matrix with $p_{i j} = ω^{i + j}$ . Then, $p^{2} \neq 0$ , when $n$ is equal to

57

No worries! We‘ve got your back. Try BYJU‘S free classes today!

55

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

58

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

56

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
B $55$
C $58$
D $56$

Suggest Corrections

Similar questions

Let $ω$ be a complex cube root of unity with $ω \neq 0$ and $P = [p_{i j}]$ be an $n \times n$ matrix with $P_{i j} = ω^{i + j}$ . Then $P^{2} = 0$ when n is equal to

Q. Let

ω

be a complex cube root of unity with

ω \neq 1

and

P = [p_{i j}]

be a n

\times

n matrix with

p_{i j} = ω^{i + j}

. Then

P^{2} \neq 0

, when

n =

Q. Let

ω

be a complex cube root of unity with

ω \neq 1

and

P = [p_{i j}]

be a

n \times n

matrix with

p_{i j} = ω^{i + j}

. Then,

P^{2} \neq 0

when

n =

Q. Let

ω

be a complex cube root of unity with

ω \neq 1

and

P = [p_{i j}]

be a

n \times n

matrix with

p_{i j} = ω^{i + j}

. Then

P^{2} \neq 0

, when

n =

Join BYJU'S Learning Program

If ω is a complex cube root of unity with ω≠1 and p=[pij] is a n×n matrix with pij=ωi+j. Then, p2≠0, when n is equal to

The correct options are B 55 C 58 D 56

If $ω$ is a complex cube root of unity with $ω \neq 1$ and $p = [p_{i j}]$ is a $n \times n$ matrix with $p_{i j} = ω^{i + j}$ . Then, $p^{2} \neq 0$ , when $n$ is equal to

The correct options are
B $55$
C $58$
D $56$