If ω is a complex number stisfying ∣∣ω+1ω∣∣=2,
then maximum distance of ω from origin is
Since maximum distance of any complex number ω from origin is given by |ω|
therefore,
|ω|=∣∣ω+1ω−1ω∣∣ ≤ ∣∣ω+1ω∣∣+∣∣1ω∣∣=2+1|ω|
⇒ |ω|2-2|ω|-1 ≤0 ⇒ 2±2√22
Hence max|ω| is 1+√2.