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Question

If ω is a cube root of unity, then (1+ω)3(1+ω2)3=

A

0

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B

ω

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C
ω2
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D
None of these
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Solution

The correct option is A

0


(1+ω)3(1+ω2)3=(ω2)3(ω)3
=ω6+ω3=ω3ω3+ω3=1+1=0

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