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Question

If ω is a cube root of unity, then (1+ωω2)5+(1ω+ω2)5=

A
32
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B
31
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C
30
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D
28
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Solution

The correct option is A 32
1+w=w2
1+w2=w
Hence,
(2w2)5+(2w)5
=25(w+w2)
=32

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