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Question

If ω is a cube root of unity, then ∣ ∣ ∣1ωω2ωω21ω21ω∣ ∣ ∣ is equal to

A
1
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B
0
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C
ω
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D
ω2
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Solution

The correct option is C 0
∣ ∣ ∣1ωω2ωω21ω21ω∣ ∣ ∣
applying R1R1+R2+R3 gives
∣ ∣ ∣000ωω21ω21ω∣ ∣ ∣=0 (1+ω+ω2=0 )
∣ ∣ ∣1ωω2ωω21ω21ω∣ ∣ ∣=0
Hence, option B.

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