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Question

If ω is a non-real cube root of unity, then the value of (1ω+ω2)5+(1+ωω2)5 is

A
16
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B
32
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C
48
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D
-32
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Solution

The correct option is B 32

(1ω+ω2)5+(1+ωω2)5=(ωω)5+(ω2ω2)5=25ω525ω525(ω5+ω10)=32(ω2+ω)=321=32


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