wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

If ω is an imaginary cube root of unity then find: (1ω+ω2)(1ω2+ω4)(1ω4+ω8) ..... to 2n factors =

A
2n+1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
22n
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
22n+1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2n
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 22n
(1w+w2)(1w2+w4)(1w4+w8)...2nterms=(1w+w2)(1w2+w)(1w+w2)...=(02w)(02w2)(02w)(02w2)...2nterms=(2w)n(2w2)n=(2w.2w2)n=4n=22n
Hence, (b) is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties of Modulus
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon