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Byju's Answer
Standard XII
Mathematics
Cube Root of a Complex Number
If ω is com...
Question
If
ω
is complex cube root of unity then value of
(
2
+
5
ω
+
2
ω
2
)
6
−
(
2
+
2
ω
+
5
ω
2
)
6
i
s
A
3
6
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B
3
7
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C
0
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D
243
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Solution
The correct option is
C
0
We know,
ω
2
=
−
1
−
ω
(
2
+
5
ω
+
2
(
−
1
−
ω
)
)
6
−
(
2
+
2
ω
+
5
(
−
1
−
ω
)
)
6
=
(
3
ω
)
6
−
(
−
3
ω
)
6
=
0
Suggest Corrections
0
Similar questions
Q.
If
ω
is a cube root of unity, then
(
2
+
5
ω
+
2
ω
2
)
6
=
(
2
+
2
ω
+
5
ω
2
)
6
=
729
Q.
If
ω
≠
1
is a cube root of unity, then value of the expression
(
1
+
2
ω
+
2
ω
2
)
10
+
(
2
+
ω
+
2
ω
2
)
10
+
(
2
+
2
ω
+
ω
2
)
10
is equal to
Q.
If
ω
is a complex cube root of unity, then the equation whose roots are
2
ω
and
2
ω
2
is
Q.
Prove that
1
1
+
2
ω
+
1
2
+
ω
−
1
1
+
ω
=
0
, Where
ω
is cube root of unity.
Q.
Prove that
1
1
+
2
ω
+
1
2
+
ω
−
1
1
+
ω
=
0
Where
ω
is imaginary cube root of unity.
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