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Question
If ω(≠1) is a cube root of unity, and (1+ω)7=A+Bω. Then (A, B) equals?
If ω(≠1) is a cube root of unity, and (1+ω)7=A+Bω. Then (A, B) equals?
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Solution
The correct option is A (1,1)
(1+ω)7=(−ω2)7=−ω14=−ω12×ω2=−ω2=1+ωOn comparing to A+Bω, (A,B)=(1,1)
(1+ω)7
=(−ω2)7=−ω14=−ω12×ω2=−ω2=1+ω
On comparing to A+Bω, (A,B)=(1,1)
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