If - - 1 is a cube root of unity- and 1-7- A-B- Then A- B equals-

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Cube Root of a Complex Number

If ω ≠ 1 is...

Question

If $ω (\neq 1)$ is a cube root of unity, and $(1 + ω)^{7} = A + B ω$ . Then $(A, B)$ equals:

(0, 1)

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(1, 1)

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(1, 0)

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(- 1, 1)

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Solution

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Similar questions

If $ω$ $(\neq 1)$ is a cube root of unity, and $(1 + ω)^{7}$ = A + B $ω$ , then (A, B) is equals:

ω (\neq 1)

(1 + ω)^{7} = A + B ω

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If ω is a complex cube root of unity and ${(1 + ω)}^{7}$ = A + B $ω$ , then (A, B) is

ω (\neq 1)

(1 + ω)^{7} = A + B ω

A, B

A, B

ω (\neq 1)

(1 + ω)^{7} = A + B ω

A

B

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