Question

If on heating liquid through ${80}^{o}C$, the mass expelled is ${\left(\frac{1}{100}\right)}^{th}$ of mass still remaining, the coefficient of apparent expansion of liquid is

• A. $126.5\times {10}^{-4}{/}^{0}C$
• B. $0.8\times {10}^{-4}{/}^{0}C$
• C. $1.25\times {10}^{-4}{/}^{0}C$
• D. $12.25\times {10}^{-4}{/}^{0}C$

Answer 1

The correct option is A $126.5\times {10}^{-4}{/}^{0}C$

Coefficient of apparent expansion is, $({\gamma }_L-{\gamma }_C)$

here, ${\gamma }_L=$ cubical constant of liquid

${\gamma }_C=$ cubical constant of container

The volume expelled is given by

$△V=V_o({\gamma }_L-{\gamma }_C)△T$

($△T$ is change in temperature)

Now, the mass expelled is ${\left(1/100\right)}^{th}$ of the mass still remaining

So, here total mass $=1.01$

$1.01=1({\gamma }_L-{\gamma }_C)80{\gamma }_L-{\gamma }_C=\frac{1.01}{80}=126.5\times {10}^{-4}/℃$

Coefficient of apparent expansion of liquid is $126.5\times {10}^{-4}/℃$