Question

If on Tuesday, Balwinder, a devotee of Lord Hanuman, eats only vegetarian food, what will Charu eat on Tuesday?

• A. Paneer Tikka
• B. Roasted Chicken
• C. None
• D. Data inadequate

Answer 1

The correct option is A

Paneer Tikka

There are originally (by default) eight possibilities to distribute the three dishes amongst A, B and C.
(PT = Paneer Tikka, RC = Roasted Chicken)
These are:
$\begin{array}{cccc}& \text{A}& \text{B}& \text{C}\\ \text{Possibility~1}& \text{PT}& \text{PT}& \text{PT}\\ \text{Possibility~2}& \text{PT}& \text{RC}& \text{PT}\\ \text{Possibility~3}& \text{PT}& \text{PT}& \text{RC}\\ \text{Possibility~4}& \text{RC}& \text{PT}& \text{PT}\\ \text{Possibility~5}& \text{RC}& \text{RC}& \text{PT}\\ \text{Possibility~6}& \text{RC}& \text{PT}& \text{RC}\\ \text{Possibility~7}& \text{PT}& \text{RC}& \text{RC}\\ \text{Possibility~8}& \text{RC}& \text{RC}& \text{RC}\end{array}$
The three constraints are:
1. If A = PT, B = C
2. If B = PT, A $\ne$ C
3. If C = RC, A = B
If we analyse the eight possibilities with respect to the constraints, the following results emerge:

$\begin{array}{ccccc}& \text{A}& \text{B}& \text{C}& \text{Result}\\ \text{Possibility~1}& \text{PT}& \text{PT}& \text{PT}& \text{Rejected, constraint 2}\\ \text{Possibility~2}& \text{PT}& \text{RC}& \text{PT}& \text{Rejected, constraint 1}\\ \text{Possibility~3}& \text{PT}& \text{PT}& \text{RC}& \text{Rejected, constraint 1}\\ \text{Possibility~4}& \text{RC}& \text{PT}& \text{PT}& \text{No contradiction with any constraint}\\ \text{Possibility~5}& \text{RC}& \text{RC}& \text{PT}& \text{No contradiction with any constraint}\\ \text{Possibility~6}& \text{RC}& \text{PT}& \text{RC}& \text{Rejected, constraint 2}\\ \text{Possibility~7}& \text{PT}& \text{RC}& \text{RC}& \text{Rejected, constraint 3}\\ \text{Possibility~8}& \text{RC}& \text{RC}& \text{RC}& \text{No contradiction with any constraint}\end{array}$
This gives us the possibility matrix for what is possible:
$\begin{array}{cccc}& \text{A}& \text{B}& \text{C}\\ \text{Final Possibility 1 (Possibility 4 in the table above)}& \text{RC}& \text{PT}& \text{PT}\\ \text{Final Possibility 2 (Possibility 5 in the table above)}& \text{RC}& \text{RC}& \text{PT}\\ \text{Final Possibility 3 (Possibility 8 in the table above) 3}& \text{RC}& \text{RC}& \text{RC}\end{array}$
Hence the answers are:
If B = PT (Final possibility 1) then Charu would also eat PT. Hence (a)