Question 130

If one angle of a triangle is $60^{\circ}$ and the other two angles are in the ratio 1 : 2, find the angles.

Open in App

Solution

Given, one angle of a triangle is $60^{\circ}$
Let the other two angles be x and 2x
We know that, the sum of all angles in a triangle is equal to $180^{\circ}$
So, $x + 2 x + 60^{\circ} = 180^{\circ}$
$\Rightarrow 3 x = 180^{\circ} - 60^{\circ} \Rightarrow 3 x = 120^{\circ} \Rightarrow x = 40^{\circ}$
So, the other two angles will be $x = 40^{\circ}$ and $2 x = 2 \times 40^{\circ} = 80^{\circ}$

Suggest Corrections

Similar questions

One angle of a triangle is $60^{\circ}$ and the other two angles are in the ratio 2:3. Find the smallest angle in the triangle.

130^{0}

60^{0}

61^{0}

1 \frac{1}{2} : 1 \frac{1}{3}

Join BYJU'S Learning Program