The answer is D.
Let the angles of a ΔABC be ∠A,∠B and ∠C
Given, ∠A=∠B+∠C . . . . .(i)
In ΔABC, ∠A+∠B+∠C=180 [sum of all the angles of a triangle is 180∘] . . . . .(ii)
From Eqs. (i) and (ii),
∠A+∠A=180∘
⇒ 2∠A=180∘
⇒ ∠A=180∘2
∴ ∠A=90∘
Hence, the triangle is a right triangle.