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Standard XII
Chemistry
Depression in Freezing Point
If one aqueou...
Question
If one aqueous solution freezes at
−
0.93
0
C
; then at what temperature it boils? [For water
k
f
=
1.86
K
k
g
m
o
l
−
1
,
k
b
=
0.52
K
k
g
m
o
l
−
1
]
Open in App
Solution
Δ
T
f
=
K
f
.
m
Δ
T
f
=
d
e
p
r
e
s
s
i
o
n
i
n
f
r
e
e
z
i
n
g
p
o
i
n
t
=
0
−
(
−
0.93
)
=
0.93
m
=
m
o
l
a
l
i
t
y
So,
0.93
=
1.86
m
m
=
0.5
k
g
/
m
o
l
Also,
Δ
T
b
=
K
b
.
m
Δ
T
b
=
e
l
e
v
a
t
i
o
n
i
n
b
o
i
l
i
n
g
p
o
i
n
t
=
T
b
−
100
0
C
(where
T
b
is boiling point of solution)
T
b
−
100
=
0.52
×
0.5
T
b
=
0.26
+
100
=
100.26
0
C
Suggest Corrections
0
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b
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0.512
K
k
g
m
o
l
−
1
and
K
f
=
1.86
K
k
g
m
o
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−
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K
f
=
1.86
K
k
g
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