If one body collides with another body of same mass at rest inelastically, the ratio of their speeds after collision shall be-
A
e
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B
1−e1+e
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C
1+e1−e
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D
1e
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Solution
The correct option is B1−e1+e Let u1 be the speed of body initially before collision. u2=0 Let v1 be speed of particle 1 after collision and v2 be speed of particle 2 after collision. Using law of conservation of momentum mu1=mv1+mv2 u1=v1+v2 Coefficient of restitution will be given by e=v2−v1u1=v2−v1v1+v2 ev1+ev2=v2−v1 Dividing throughout by v2 and rearranging leads to v1v2=1−e1+e