If one cubic dm of a gas weighs 2.5 g at STP, its molecular weight (in gram) is :

56 g

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11.2 g

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22.4 g

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224 g

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Solution

The correct option is A 56 g
$1 d m^{3}$ weighs $2.5 g$ , then $22.4 d m^{3}$ weighs $22.4 \times 2.5 = 56 g$

1 mole of gas at STP occupies 22.4 dm $^{3}$ .

Molecular weight is the weight of 1 mole of gas so the weight is $56 g$

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If one cubic dm of a gas weighs 2.5 g at STP, its molecular weight (in gram) is :

The correct option is A 56 g1 dm3 weighs 2.5 g, then 22.4 dm3 weighs 22.4×2.5=56 g1 mole of gas at STP occupies 22.4 dm3.Molecular weight is the weight of 1 mole of gas so the weight is 56 g

The correct option is A 56 g
$1 d m^{3}$ weighs $2.5 g$ , then $22.4 d m^{3}$ weighs $22.4 \times 2.5 = 56 g$

1 mole of gas at STP occupies 22.4 dm $^{3}$ .

Molecular weight is the weight of 1 mole of gas so the weight is $56 g$