Question

If one end of a diameter of the circle $x^2+y^2-4x-6y+11=0$ be (3, 4), then the other end is

• A. (0, 0)
• B. (1, 1)
• C. (1, 2)
• D. (2, 1)

Answer 1

The correct option is C (1, 2)

Centre is (2, 3). One end is (3, 4).
Let the other end be P(x,y).
Centre is the midpoint of the two points of the diametre.
Using midpoint formula we get P(x,y) = (1,2).