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Question

If one end point of the focal chord of the parabola y2=4ax is (1,2), then second end point lies on

A
x2y+2=0
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B
xy+2=0
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C
xy2=0
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D
x2+xyy1=0
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Solution

The correct option is D x2+xyy1=0
For y2=4x
a=1 then (1,2)(t21,2t1)
By comparing, we get,
t1=1
for second end point (t22,2t2)
and
t1t1=1t2=1
So, second end point will be (1,2)
Now checking options
12×(2)+2=0 , satisfied
1×(2)+2=0 , satisfied
1×(2)2=40 , Not satisfied
12+1×(2)(2)1=0 , satisfied

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